Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
c
Step-by-step explanation:
Answer:
y=-7
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=0(x-5)
y+7=0
y=0-7=-7
I don’t understand your question
Answer:
first thing to do is get up from your sit and go cry because that question is to hard