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katovenus [111]
3 years ago
5

Which one? Do i chose

Mathematics
2 answers:
Georgia [21]3 years ago
7 0

Answer:

226 inches cube

Step-by-step explanation:

The volume of the cylinder is the area of the base X height therefore it would be 3^2 * 3.14 * 8 = 72 * 3.14 = 226.08.

disa [49]3 years ago
7 0

Answer:

151 in^3

Step-by-step explanation:

pi x 3^2 x 5.5 (the approximate water level)

= 155

151 is the closest answer

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How many 5/8 -foot pieces of wood can you cut from a board that is 4/5/8 ft long?
Vadim26 [7]

Answer:

7

Step-by-step explanation:

4 5/8 divided by 5/8 = 7 2/5

3 0
3 years ago
729 to the power of 1 over 3
vivado [14]
So \frac{ 721^{1} }{3} ?

if so, the answer is 240\frac{1}{3}

4 0
3 years ago
Solve for x ... please help
Mrac [35]

Answer:

7x + 49 \degree = 2x + 94\degree \\ 7x - 2x = 94\degree - 49 \degree \\ 5x = 45\degree \\ x =  \frac{45}{5}  \\ x = 9 \\ check \\ 7(9) + 49 = 112\degree \\ 2(9) + 94 = 112\degree

5 0
2 years ago
8 is 80% of what number? If necessary, round to the nearest tenth.
prisoha [69]

Answer:

10

Step-by-step explanation:

You can do 8 / 0.8 to get 10

3 0
3 years ago
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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