Y=10x+1
x=-1→y=10(-1)+1=-10+1→y=-9
x=0→y=10(0)+1=0+1→y=1
x=1→y=10(1)+1=10+1→y=11
x=5→y=10(5)+1=50+1→y=51
x y
-1 -9
0 1
1 11
5 51
Nadia = 3x than Jim
Paul = 25+ than Nadia
Jim = ?
Nadia and Paul = 85
85-25 = 60
(Subtract Nadia's and Paul's stickers all together with the stickers that Paul have more so both of the stickers are balance)
Nadia = 60/2 =30
Paul = 30+25 =55
Jim= 30/3=10
#Jim have 10 stickers
First, find the length of one side of a square:
Area = side²
11 = s²
s = √(11) cm
Since there are 8 squares on each side, multiply the length of one square by 8 to get the length of 8 squares.
√(11) * 8 = 8√(11) ≈16.5 cm
Hope this helps!
please explain what question you are talking about since there is 6 questions on the paper.
