"Main" goes in the blank. For example in C++ all of your code goes in the main function.
Visible outline.
hope this helps
Answer:
In assembly language, two instructions control the use of the assembly language procedure.
CALL pushed the control to the return address onto the stack and transferred the control.
RET instruction returns the address that placed on the stack by a call instruction.
Explanation:
Action RET instruction
- The RET instruction pops the address and returns off the stack, which is pointed by the stack pointer.
- The stack is LIFO in memory at a particular location, and the pointer points offset from the stack location.
RET instruction does its job by consulting the register and memory state at the point when it is executed.
In RET instruction, only register and memory state is executed. Call instruction must save that address that figure out in a register and memory location.
Option A because the environment should be selected for which the changes are to be applied. In a time Force IDE has many project environments for example maybe a java project and C++ project would be there on sandbox, so the environment selection is important.
Option B because the related changed sets should be specified so that other developers that have access to the project can see the changes being made.
Option D The data fields that are needed to be deployed should also be provided so that the updated version can be seen by other developers.
Rejected Options :
Option C user name and password has nothing to do with the production environment because if the user has it only then it can come and make changes.
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
