Answer:c ll d
Explanation:
cus they are inside ()--parantheses
Answer:
a=4 , b=1
Explanation:
I'm not a computer science major at all but I think I can help you with this code.
Our program wants us to add 2 to a get new a value while also subtracting 1 from b value to obtain new b value. We we want to for for as long b is not 0 and a/b is nonnegative.
One round we get:
New a=0+2=2
New b=3-1=2
Let's see if we can go another round:
New a=2+2=4
New b=2-1=1
We can't go another round because b would be negative while a is positive which would make a/b negative. So our loop stops at this 2nd round.
a=4 , b=1
Other notes:
2nd choice makes no sense because a is always going to increase because of the addition on a and b was going to decrease because of the subtraction on it.
Third choice makes no sense because a/b doesn't even exist.
Fourth choice a/b is negative not nonnegative.
Answer:
it doesn't? maybe it helps by resetting it but other than that I don't think It does anything
Answer:
couple.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
s1=[1,2,3]
s2=[4,5,6]
print(couple(s1,s2))
enum.py
def couple(s1,s2):
newlist = []
for i in range(len(s1)):
newlist.append([s1[i],s2[i]])
return newlist
def enumerate(s,start=0):
number_Array=[ i for i in range(start,start+len(s))]
return couple(number_Array,s)
s=[6,1,'a']
print(enumerate(s))
print(enumerate('five',5))
Explanation:
Answer:
<em> where the attacker secretly relays and possibly alters the communications between two parties who believe that they are directly communicating with each other.</em>
Explanation: