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Zinaida [17]
3 years ago
12

Calculate the mass of 100 mL of hexane with a density of 0.66 g/mL.

Chemistry
1 answer:
algol [13]3 years ago
3 0

Answer:

<h2>The answer is 66 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of hexane = 100 m L

density = 0.66 g/mL

The mass is

mass = 0.66 × 100

We have the final answer as

<h3>66 g</h3>

Hope this helps you

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Potassium Chloride = KCl

KCl has a molar mass of: 39.0983g+35.4530g=74.5513g

The number of moles of KCL we are adding is: 2g/(74.5513g/mol) = 0.02683 mol

But you have to keep in mind that salts in water dissociate:

KCl -> K+ + Cl-

So 1 mole KCl is 2 osmoles (because it’s two particles)

So if you add 0.02683 moles, you are adding 0.02683*2 = 0.05366 osmoles. If you dissolve them in 1 liter, you have a solution 0.05366 OsM = 53.66 mOsM

D5W = dextrose 260 mOsM

1/2 Normal Saline = has half of the normal saline concentration - a normal saline solution has the same sodium chloride concentration as blood serum = 154 mOsm

You have to sum up all the osmolarities:

<span>=  </span>53.66 mOsM + 154 mOsM + 260 mOsM = 467.66 mOsM




6 0
3 years ago
Question 8 of 10
olga nikolaevna [1]

Answer:

C. 1:30

Explanation:

The toy car is .5 feet long and the actual car is 15 feet long

This gives you a ratio of

.5:15

Now for everything you have to remember this

.5:15

=1:30

=2:45

=3:60

C is the only answer that matches any of the ratios above.

Even if you went farther in the ratios none of them would match this ratio.

Hope this helped.

=)

3 0
3 years ago
A solution of sulfuric acid is titrated with a solution of sodium hydroxide to the phenolphthalein end point. The sample of sulf
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Answer:

a. 2NAOH + H2SO4 —> NA2SO4 + 2H2O

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Explanation:Please see attachment for explanation

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Type the correct answer in the box. Express your answer to two significant figures.
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Answer: The percent yield of zinc carbonate is 5.91 %

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

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ZnI_2 is the limiting reagent as it limits the formation of product and Na_2CO_3 is the excess reagent.  

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According to stoichiometry :

1 mole of produce =  1 mole of

Thus 1.7 moles of ZnI_2 will produce=\frac{1}{1}\times 1.7=1.7moles  of ZnCO_3

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3 years ago
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Answer: Fluorine (see explanation)

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