The molar mass of monopotassium phosphate is 136.09 g/mol. How many moles of monopotassium phosphate are needed to make 250.0 ml
1 answer:
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The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.
<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.
The equation of the reaction is given below:
The mole ratio of both reactants and product is 1 : 1
- moles = mass/molar mass
molar mass of copper sulfate = 160 g
molar mass of Cu = 64
molar mass of iron = 56 g
- mole ratio of iron to copper = 1 : 1
moles of Cu in 1.5 g = 1.5/64 = 0.00234
mass of iron required = 0.00234 × 56 = 1.31 g of iron
Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.
Learn more about mole ratio at: brainly.com/question/19099163
Answer : The theoretical yield of water formed from the reaction is 0.54 grams.
Solution : Given,
Mass of HCl = 1.1 g
Mass of NaOH = 2.1 g
Molar mass of HCl = 36.5 g/mole
Molar mass of NaOH = 40 g/mole
Molar mass of = 18 g/mole
First we have to calculate the moles of HCl and NaOH.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of HCl react with 1 mole of NaOH
So, 0.030 mole of HCl react with 0.030 mole of NaOH
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 1 mole of react to give 1 mole of
So, 0.030 moles of react to give 0.030 moles of
Now we have to calculate the mass of
Therefore, the theoretical yield of water formed from the reaction is 0.54 grams.