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mafiozo [28]
3 years ago
14

an instructor grades on a curve by assuming that grades on a test are normally distributed. If the average grade is 80 and the s

tandard deviation is 8 find the test score for each grade interval if the instructor assigns grades
Mathematics
1 answer:
sweet [91]3 years ago
3 0

Step-by-step explanation:

According to normal distribution curves following a bell curve formula, it is followed that

34% of people will lie between Mean point and one positive standard deviation

34% of people will lie between Mean point and one negative standard deviation

14% of people will lie between Mean point and two positive standard deviation

14% of people will lie between Mean point and two negative standard deviation

2% of people will lie between Mean point and three positive standard deviation

2% of people will lie between Mean point and three negative standard deviation

Now following this principle, we are given that mean score is 80 and standard deviation is 8, hence the interval for grades would be;

Grade A ; Score greater than 96

Grade B : Score greater than 88 and less than or equal to 96

Grade C : Score greater than 80 and less than or equal to 88

Grade D : Score greater than 72 and less than or equal to 80

Grade E : Score greater than 64 and less than or equal to 72

Grade F : Score less than 64

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In a certain month, Mason spent 1/6 of his salary in the first three days and $800 in the following ten days and after that he w
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<h3>Answer:   $2400</h3>

========================================================

Explanation:

x = Mason's salary in dollars for that month

x/6 = one-sixth of his salary

x/6+800 = total amount spent (the x/6 dollars and $800 combined)

In total, he spent half his salary. This means he spent x/2 dollars for the month overall.

Set the two items equal to one another. Solve for x.

x/6 + 800 = x/2

6(x/6 + 800) = 6*(x/2) ... see note at the bottom of the page

x+4800 = 3x

4800 = 3x-x

4800 = 2x

2x = 4800

x = 4800/2

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His monthly salary is $2400

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-------

Note: I multiplied both sides by 6 to clear out the fractions. The value 6 is the LCD in this case.

7 0
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