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Leona [35]
3 years ago
10

Charlie is at a small airfield watching for the approach of a small plane with engine trouble. He sees the plane at a angle of e

levation of 32. At the same time time, the pilot radios Charlie and reports the planes altitude is 1,700ft. Charlies eyes are 5.2ft from the ground. Find the difference from Charlie to the plane? Please show how you know!

Mathematics
1 answer:
liubo4ka [24]3 years ago
5 0
First find the vertical distance from Charlie to the plane by subtracting the altitude of Charlie's eyes from the altitude of the plane: 1700-5.2=1694.8 ft. Let d be the distance from Charlie to the plane. Use the trignometric relationship in the right triangle: sin32=1694.8/d. d=3198 ft.
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The point (-7,4) in on the terminal side of an angle t. Find sec (t) to two decimal places.
Sliva [168]

Answer:

  -1.15

Step-by-step explanation:

The tangent of the angle can be found as ...

  tan(t) = (y-coordinate)/(x-coordinate) = -4/7

The secant of the angle is related by ...

  sec(t)² = tan(t)² +1 = (-4/7)² +1 = 65/49

Then the secant of this 2nd-quadrant angle is ...

  sec(t) = -√(65/49) = -(√65)/7 ≈ -1.15

6 0
3 years ago
There is a bag filled with 3 blue and 4 red marbles.
tresset_1 [31]

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the <em>hypergeometric </em>distribution is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There is a total of 3 + 4 = 7 marbles, hence N = 7.
  • Of those, 3 are blue, hence k = 3.
  • 2 marbles will be taken, hence n = 2.

The probability of getting 2 of the same colour is the sum of P(X = 0), which is both red, with P(X = 2), which is both blue, then:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,7,2,3) = \frac{C_{3,0}C_{4,2}}{C_{7,2}} = 0.2857

P(X = 2) = h(2,7,2,3) = \frac{C_{3,2}C_{4,0}}{C_{7,2}} = 0.1429

Hence:

p = P(X = 0) + P(X = 2) = 0.2857 + 0.1429 = 0.4286

0.4286 = 42.86% probability of getting 2 of the same colour.

You can learn more about the hypergeometric distribution at brainly.com/question/4818951

3 0
2 years ago
The volumes of two spheres are 729 in3 and 27 in3.
forsale [732]
I think it is gonna be 2:7
8 0
3 years ago
Can someone plz help me
Pani-rosa [81]

Answer:

I got 172.05

Step-by-step explanation:

I used a calculator on goo gle calculatorsoup.com

5 0
3 years ago
POTW 1
pychu [463]

Answer:

9%

Step-by-step explanation:

I went on calculator .__.

6 0
3 years ago
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