Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
step #1: Set Realistic and Achievable Goals
Step-by-step explanation:
Answer:
-8
Step-by-step explanation:
5(x+12)= 20
5x+60= 20
5x= -40
x= -8
1. 9.5x + 1.5
2. 9x + 36
3. 4.8x + 2
4. 22x + 2