Answer:
D
Step-by-step explanation:
Let
x--------> the length side of the square base
h--------> the height of the box
we know that
<u>the volume of the box is equal to</u>

so

<u>the surface area of the box is equal to</u>
(remember that the box is open)
area of the base=
Perimeter of the base=
height=(h) m

substitute

we know that
the value of x can not be negative and the denominator can not be zero
therefore
<u>the answer is</u>
the domain of SA is x> 0
the domain is the interval-------------> (0,∞)
10 3/5 is the correct answer
Answer:
This is an isosceles right triangle, then we have
2 x u^2 = [6sqrt(2)]^2
<=> 2 x u^2 = 72
<=> u^2 = 36
<=> u = 6
Hope this helps!
:)
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3