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wlad13 [49]
3 years ago
9

The two popular measures for quantitatively determining if a process is capable are

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0

Answer:

D

Step-by-step explanation

Process capabilitty ration and process capability index are statistical tools which are often used to produced output within a limit.

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Please help, will give brainliest!<br>(please explain how as well)​
vovikov84 [41]

Answer:

C

Step-by-step explanation:

Since GJ bisects ∠ FGH , then ∠ FGJ = ∠ JGH = x + 14

∠ FGH = ∠ FGJ + ∠ JGH , substitute values

4x + 16 = x + 14 + x + 14 = 2x + 28 ( subtract 2x from both sides )

2x + 16 = 28 ( subtract 16 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

Thus

∠ FGJ = x + 14 = 6 + 14 = 20° → C

4 0
3 years ago
Find the value of x in 2x+20=3x-8
Savatey [412]

Answer:

X=28

Step-by-step explanation:

3x-8=2x+20. So x=28

8 0
3 years ago
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Weekly Math #20 answer ​
zmey [24]

Answer:

Could we get the question please?

Step-by-step explanation:

3 0
4 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
An equilateral triangle has three equal sides.
Flauer [41]

Answer:

Step 1. Perimeter P means adding up all three sides of a triangle.

Step 2. Then P=s+s+s=3s where s is the length of the side of the equilateral triangle.

Step 3. ANSWER: Perimeter P=3s.

I hope the above steps and explanation were helpful.

Step-by-step explanation:

HOPE THIS HELPS

6 0
3 years ago
Read 2 more answers
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