If it decreases at 4% every year, then its value becomes:
100% - 4% = 96% = 96/100 = 0.96
At the end of the 1 year its value becomes: 150*(0.96)
At the end of the 2 years its value becomes: 150*(0.96)*(0.96) = 150*(0.96)²
At the end of the 3 years its value becomes: 150*(0.96)*(0.96)*(0.96) = 150(0.96)³
So similarly at the end of 12 years, its value becomes 150*(0.96)¹²
=50*(0.96)¹² simplify with calculator.
<span>≈ 91.91
Value at the end of 12 years becomes ≈ $</span><span>91.91
I hope this helps.
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Y=3x+4.....eq.(i) x+4y=-10....(eq.ii) putting value of y in eq.(ii),we get, x+4(3x+4)=-10 or x+12x+16=-10 or,13x=-10+16 or,13x=6 ●#x=6÷13 putting value if x in eq.(i),we get y=3(6÷13)+4 or,y=18÷13+4 or,y=(18+52)÷13 ●#y=70÷13
Answer:
6 units
Step-by-step explanation:
The formula for a trapezoid is ((b1+b2)/2)h.
Here, we see b1 = 8 and b2 = 17.
If the area of the trapezoid is 75, we can make the equation :
75 = ((8+17)/2)x , where we would solve for x.
First, we simplify the right side of the equation :
75 = (25/2)x
Multiply both sides by 2 to get rid of the "/2"
150 = 25x
Then divide both sides by 25.
6=x
steps are to
Combine like terms
Divide both sides of the equation by the same term
simplify
k = -6
First convert the complex number to polar form
|5 - 5sqrt3i| = 25sqrt10
argument = arctan - sqrt3 = -pi/3
so 5 - 5sqrt3i = 25sqrt10(cos(-pi/3) + i sin(-pi/3))
the angle is in the 4th quadrant so we could write it as 2pi-pi/3 = 5p/3
= 25sqrt10(cos 5pi/3 + i sin 5pi/3)
Now if r(cosx + isin x) is a 5th root of 5-5sqrt3i then
r^5(cos x + i sinx)^5 = 25sqrt10(cos 5pi/3 + i sin 5pi/3)
r^5 = 25sqrt10 and cos5x + i sin 5x = cos 5pi/3 + i sin 5pi/3
i have to go urgently so i have to leave it to you to finish this
