Which of the following pairs of units of measurement are equivalent to each other?

Mathematics

1 answer:

evablogger [386]3 years ago

3 0

Answer:

The correct options are:

cubic decimeter and liter
cubic centimeter and milliliter

Step-by-step explanation:

1) The 1 cubic decimeter is equal to the 1 liter.

$dm^3= 1 L$

2) The 1 cubic centimeter is equal to the 1 milliliter.

$cm^3=1 mL$

3) Since,1 cubic decimeter is equal to the 1 liter.

So, $dm\neq 1L$

4) Since, 1 quart = 0.946353 L

$quart\neq liter$

5) Since,The 1 cubic centimeter is equal to the 1 milliliter.

So, 1 millimeter ≠ 1 deciliter

6) Since,1 gram = 0.035274 ounces

So, 1 gram ≠ 1ounce

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Murljashka [212]

Answer:

Step-by-step explanation:

when x = 0

6 0

3 years ago

A community theater uses the function p (d) = (-4d+40) (d−40) to model the profit (in dollars) expected in a weekend when the ti

fomenos

The theater make the maximum profit at d = $25. Then the maximum profit of the theatre is $ 900.

<h3>What is differentiation?</h3>

The rate of change of a function with respect to the variable is called differentiation. It may be increasing or decreasing.

A community theater uses the function P(d) = (− 4d + 40) (d − 40) to model the profit (in dollars) expected on a weekend when the tickets to a comedy show are priced at d dollars each.

Then the maximum profit of the theatre will be

The function is P(d) = (− 4d + 40) (d − 40)

Differentiate the function with respect to d and put it equal to zero for maximum or minimum profit.

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= 0\\\\\dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) &= 0\\\\(-4d+40) -4 (d-40) &= 0\\\\-8d + 200 &= 0\\\\d &= 25 \end{aligned}$

Then the checking for maximum or minimum, again differentiate, we have

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(-8d + 200) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= -8\\\\ \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) & < 0\end{aligned}$