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frutty [35]
3 years ago
6

"Twenty-eight is more than four times another number" can be shown by the inequality 28 > 4n. Select the values of n which co

uld possibly make this a true statement.
choose all answers that are correct.....

A. n>7
B.4
C.8 1/3
D7
Mathematics
1 answer:
Virty [35]3 years ago
6 0
The only accurate answer would be B. 7×4 is 28 so 28 isn't greater. So it can't be any number higher than 6 and the only one lower than 6 is 4
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Ten kids can go to the water park for $95. How many can go if there is $200?
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Answer:

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I need the answer for this problem please
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Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

4 0
3 years ago
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Answer:

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Step-by-step explanation:

For the first one, we know that in order to solve the equation, we need to add 3 to both sides of the equation. When you add a value to both sides of the equation, you're using the addition property of equality.

For the second one, we know that in order to solve the equation, we need to multiply both side by 1/6 (to cancel the 6 out on the left side). When you multiply something to both sides of the equation, you're using the multiplication property of equality.

For the third one, we know that in order to solve the equation, we must multiply both sides of the equation by 5. Like the second problem, this would be the multiplication property of equality (since you're multiplying both sides of the equation by the same thing).

3 0
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