49.35 litres
47 times 1.05=49.35
(Sheldon got it right first)
The numbers are: 36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables;
"x" and "y" .
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x + y = 47 .
y − x = 25.
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Since: " y − x = 25 " ;
Solve for "y" in terms of "x" ;
y − x = 25 ;
Add "x" to each side of the equation:
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y − x + x = 25 + x ;
to get:
y = 25 + x .
Now, since:
x + y = 47 ;
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47 ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x = 22 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; and to solve for "x" ;
2x / 2 = 22 / 2 ;
x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
to isolate "y" on one side of the equation; and to solve for "y" ;
11 + y − 11 = 47 − 11 ;
y = 36 .
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So: x = 11 , y = 36 ;
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Let us check our work:
y − x = 25 ;
36 − 11 =? 25 ? Yes!
x + y = 47 ;
36 + 11 =? 47 ? Yes!
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The numbers are: 36 and 11 .
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Answer:b
Step-by-step explanation:it equals out to 180°
4 2/3. add the twos and keep the 2/3
Answer:
All non zero digits count in significant digits.
(a) is correct option.
Step-by-step explanation:
Given that,
1.4 has 2 significant digits.
We know that,
Significant digits :
All non zero digits count in significant digits.
All zero which is present in between two significant digits it is also significant.
Leading zero is not count as significant.
Trailing zero is count as significant.
We need to find 1.4 has 2 significant digits as a result of which rule
Using given rules
1.4 has 2 significant digits it is follows the rule of all non zero digits count in significant digits.
Hence, All non zero digits count in significant digits.
(a) is correct option.
