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dusya [7]
3 years ago
8

Find the values of x and a please!!

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Eight more than one -<br> fourth of d
alexandr1967 [171]

Answer:

(1/4*d) + 8

Sorry but there's no explanation cause its quick

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%20-%20%20%5Cfrac%7Bx%7D%7B2%7D%20%20%3C%203%20" id="TexFormula1" title="3 - \frac{x}{2} &l
Sergio [31]
The first step for solving this is to cancel equal terms on both sides of the inequality.
- \frac{x}{2} < 0
Now multiply both sides of the inequality by -2 and flip the inequality sign.
-2 × (- \frac{x}{2}) > -2 × 0
Remember that multiplying two negatives together always equals a positive,, so the expression changes to the following:
2 × \frac{x}{2} > -2 × 0
Reduce the numbers with 2.
x > -2 × 0
Any expression multiplied by 0 equals 0,, so the correct answer to your question will be:
x > 0
Let me know if you have any further questions.
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8 0
4 years ago
What is the mean?<br> 69 71 85<br> 96<br> 93 78 89
nadezda [96]

Answer:

83

Step-by-step explanation:

Mean is the average

so add all the numbers up and divide it by how many numbers you have

(69+71+85+96+93+78+89)/ 7=83

3 0
3 years ago
What is the equation of a line that has a slope of −1/2 and a y-intercept of 3? Express your answer in slope-intercept form.
alukav5142 [94]

\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{10em}\underset{\qquad y-intercept}{\stackrel{slope}{y = \stackrel{\downarrow }{-\cfrac{1}{2}}x}+\underset{\uparrow }{3}}

8 0
3 years ago

jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or,                    (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or,                    (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or,                    (P) = 100 yards + 209.33 yards

or,                    (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0
4 years ago
Read 2 more answers
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