S equals 3 times B, I think.
Hope I helped c:
Inverse variation is of the form y=k/x (direct variation is of the form y=kx)
We are given that x=2 when y=1 so using the inverse form y=k/x we can solve for the constant of variation...
1=k/2
k=2
so the equation is:
y=2/x now they want us to find y when x=-1 so
y=2/-1
y=-2
Answer:
d) 135º
Step-by-step explanation:
Note that the angle DCU is the sum of the angles DCB and BCU. The angle DCB is 90º because A B C D is a square, then all its angles are equal to 90º.
After attaching B U C to A B C D, we obtain a trapezoid A U C D. Since A U C D has at least one pair of parallel sides, then AU should be parallel to CD, thus the angle CBU must be 90º.
B U C is isoceles, so we conclude that other two angles must have the same size, and due to the sum of the angles of a triangle being 180º, then both BUC and BCU are equal to 45º
As a result, the angle DCU is equal to 90º+45º = 135º. Option d is the correct one.
30,77,55,71,19,40,10,5,7,6
Answer:
<h3>1. t=10</h3><h3>2. t=4</h3><h3>3. t=40</h3>
Step-by-step explanation:
Isolate the term of t from one side of the equation.
<h3>1. 4t=40</h3>
First, you have to divide by 4 from both sides.
4t/4=40/4
Solve.
Divide the numbers from left to right.
40/4=10
<h3><u>
t=10</u></h3>
<h3>2. 10+t=14</h3>
<u>First, change sides.</u>
t+10=14
<u>Then, subtract by 10 from both sides.</u>
t+10-10=14-10
<u>Solve.</u>
<u>Subtract the numbers from left to right.</u>
14-10=4
<h3><u>
t=4</u></h3>
<h3>3. 70-t=30</h3>
First, subtract by 70 from both sides.
70-t-70=30-70
Solve.
30-70=-40
<u>Rewrite the problem down.</u>
-t=-40
Divide by -1 from both sides.
-t/-1=-40/-1
<u>Solve.</u>
<u />
<u>Divide the numbers from left to right.</u>
-40/-1=40
<h3><u>
t=40</u></h3>
- <u>Therefore, the correct answer is t=10, t=4, and t=40.</u>
I hope this helps! Let me know if you have any questions.
