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2 years ago

The perimeter of a rectangular table is 8 m.

Mathematics

1 answer:

ipn [44]2 years ago

8 0

Answer:

The side lengths are 1.5m and 2.5m.

Step-by-step explanation:

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The scale on a map of Roswell, New Mexico is 1 inch : 0.5 mile. If two buildings in Roswell are 2.3 miles apart in real life, th

Nataly_w [17]

Im not too sure but I think its 4.6,because 1 in :.5 mile. As a whole, .5 can go into 2, 4 times, then whats left over also gets divided into .6. Add those together and youll get 4.6

4 0

3 years ago

FIND PR.PLS HELP BRAINLIEST...

slega [8]

Answer:

6.2 units.

Step-by-step explanation:

We are given two angles and an opposite corresponding side. To solve for an unknown side, we can use the law of sines.

$\frac{8}{sin(90)}=\frac{x}{sin(180-39-90)}=\frac{x}{sin(51)}$

Cross multiplying and solving will get you this:

$x=\frac{8(sin(51))}{sin(90}$

Which can simplify to:

$x=8(sin(51))$

Which putting into a calculator gets you:

$x=6.2$

So the line PR is 6.2 units long.

6 0

3 years ago

There are 9 classes of 25 students each 4 teachers in two times as many chaperones as teachers each bus hold a total of 45 peopl

Tanya [424]

Answer:

Least number of bus require for trip = 5 buses (Approx)

Step-by-step explanation:

Given:

Total number of classes = 9

Number of student in each class = 25

Number of teacher = 4

Number of chaperones = Double of teacher

Bus hold = 45 people

Find:

Least number of bus require for trip

Computation:

Total number of student = 9 × 25

Total number of student = 225

Number of chaperones = 4 × 2

Number of chaperones = 8

Total people = 225 + 8 + 4

Total people = 237

Least number of bus require for trip = Total people / Bus hold

Least number of bus require for trip = 237 / 45

Least number of bus require for trip = 5.266

Least number of bus require for trip = 5 buses (Approx)

6 0

2 years ago

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation

Nutka1998 [239]

Answer:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.917,0.303)$

Where $\mu=0.917$ and $\sigma=0.303$

We have the following info from a sample of n =37:

$\bar X= 0.872$ the sample mean

And we want to find the following probability:

$P(\bar X \leq 0.872)$

And we can use the z score formula given by;

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for the value of 0.872 we got:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

6 0

3 years ago

Either enter an exact answer in terms of T or use 3.14 for 7 and enter your answer as a decimal.

muminat

Answer:

N CCX XN

Step-by-step explanation:

7 0

2 years ago