first one is 0 second one is 2 and then the last one is 0
Answer:
whoa
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
=> -x+4
<u><em>Given that x = -2</em></u>
=> -(-2)+4
=> 2+4
=> 6
Simplifying
(0.75x + 6) + -1(2.5x + -1.9) = 0
Reorder the terms:
(6 + 0.75x) + -1(2.5x + -1.9) = 0
Remove parenthesis around (6 + 0.75x)
6 + 0.75x + -1(2.5x + -1.9) = 0
Reorder the terms:
6 + 0.75x + -1(-1.9 + 2.5x) = 0
6 + 0.75x + (-1.9 * -1 + 2.5x * -1) = 0
6 + 0.75x + (1.9 + -2.5x) = 0
Reorder the terms:
6 + 1.9 + 0.75x + -2.5x = 0
Combine like terms: 6 + 1.9 = 7.9
7.9 + 0.75x + -2.5x = 0
Combine like terms: 0.75x + -2.5x = -1.75x
7.9 + -1.75x = 0
Solving
7.9 + -1.75x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7.9' to each side of the equation.
7.9 + -7.9 + -1.75x = 0 + -7.9
Combine like terms: 7.9 + -7.9 = 0.0
0.0 + -1.75x = 0 + -7.9
-1.75x = 0 + -7.9
Combine like terms: 0 + -7.9 = -7.9
-1.75x = -7.9
Divide each side by '-1.75'.
x = 4.514285714
Simplifying
x = 4.514285714
Answer:
The triangle has one solution. The remaining side c ≈ 4 and remaining angles B = 30°; C = 31°.
Option D is correct.
Step-by-step explanation:
if angle A is obtuse and if a > b then the triangle has one solution
We are given ∠ = 119° which is obtuse and side a= 7 and side b - 4 i.e 7>4 so, the triangle has one solution.
Finding remaining side c and ∠B and ∠C
Using Law of sines to find ∠B
a/sin A = b/sin B
7/sin 119° = 4/sin B
7 * sin B = 4 * sin 119
7*sin B = 4(0.874)
sin B = 3.496/7
B = sin^-1(0.4994)
B = 29.96 = 30°
We know that sum of angles of triangle = 180°
So, 180° = 119° + 30° +∠C
180° = 149° + ∠C
=> ∠C = 180° - 149°
∠C = 31°
Now finding c
b/sin B = c /sin C
4/Sin 30 = c/sin 31
4* sin 31 = c*sin 30
4*0.515 = c* 0.5
=> c = 4*0.515/0.5
c = 4.12 ≈ 4
So, Option D one solution; c ≈ 4; B = 30°; C = 31° is correct.
