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2 years ago

Given the function y=log2(x-3)+1 state the domain

1 answer:

3 0

I think the answer is:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(
−
∞
,
∞
)
(
-
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
{
x
|
x
∈
ℝ
}
Hope this helped:)

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Which number is the same distance away from -12 as 2?

Ray Of Light [21]

Answer:

-26

Step-by-step explanation:

2 is 14 away from -12. The other number that is 14 away from -12 is -26.

-12 + x = 2

x = 14

-12 - 14 = -26

4 0

2 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

Convert -18° to radians.

Fiesta28 [93]

0.314159

Is the answer

5 0

3 years ago

Hello guys can you help me with this?

Katyanochek1 [597]

Answer:

Step-by-step explanation:

1. Title of the graph → Comparison of the Plant Growth

2. y-axis represents the height of the plants in centimeters.

3. On day 2:

Height of plant A (plant outside) = 5.1 cm

Height of plant B (plant near the window) = 2.25 cm

4. Plant outside shows great increase in the height.

On day 5,

Height of the plant outside = 6.75 cm

Growth in height from day 2 to day 5 = 6.75 - 5.1

= 1.65 cm

Height of the plant near the window = 2.5 cm

Growth in height of the plant from day 2 to day 5 = 2.5 - 2.25

= 0.25 cm

Therefore, plant outside shows the great increase in height.

5. Plant near the window grew 0.25 cm in height.

4 0

2 years ago

When can you use proportional reasoning to solve a problem?

Natali [406]

Answer:

Step-by-step explanation:

I DID THAT

7 0

3 years ago

Read 2 more answers