Answer:
False
Step-by-step explanation:
Every where I looked it shows nothing about the Coriolis effect is the measurement of wind speed based on friction from mountains.
5.5-3b = 2b-6.25
5.5+6.25 = 2b+3b
11.75 = 5b
11.75/5 = 5b/5
2.35 = b
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
Answer:
Step-by-step explanation:
Depends on the tree.
If it's like a pine or spruce, then I would use maybe 2 inches lattitude. If it's really leafy with big leaves, perhaps a little more lattitude is needed, like maybe 1/2 a foot.
It also depends on the season. Unless the pine or spruce is covered with snow, I wouldn't change the latitude. If it is covered with snow, knock the snow off.
For something like a maple in winter, I'd reduce the latitude to 3 inches......
Answer:
The function is 
domain is 0 to 0.2 hour.
range is 0 to 2 miles.
Step-by-step explanation:
Given that,
Average velocity = 10 miles/hour
Time = 12 min = 0.2 hour
We need to write a function that models the student's distance from home
Using formula of distance
Where, v = velocity
t = time
d = distance
Put the value into the formula
This is a function.
We know that,
Domain :
Domain shows the time.
So, domain = 0 to 0.2 hour
Range :
Range shows the distance.
The range at t =0,
Put the value of t in the function
The range at t =0.2 hour
So. range = 0 to 2 miles
Hence, The function is
domain is 0 to 0.2 hour
range is 0 to 2 miles
