M = negative 1 I hope this helps
The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.
<h3>What is the solution of the equation as given in the task?</h3>
The given equation is; (y-5)/2=(y+6)/3.
Hence, by multiplying the equation by 6, we have;
3(y-5) = 2(y+6)
3y -15 = 2y +12
y = 27.
Hence, it follows that the value of y which is a solution to the equation is; y = 27.
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Answer:
0;3,6;9................................
I: 635=dimes*10+quarters*25
or shorter
635=d*10+q*25
II: d=q*3+3
Substitute II (d=3q+3) into I to replace d:
635=d*10+q*25
635=(3q+3)*10+q*25
635=30+30q+25q
605=55q
11=q
-> 11 quarters
"What expression represents the number of dimes if q represent quarters"
insert q=11 into II:
II: d=q*3+3
d=11*3+3
d=33+3
d=36
