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sp2606 [1]
3 years ago
12

Which expression demonstrates the use lf the commutative property of addition in the first step of simplifying the expression (-

1+i) + (21+5i)?
Mathematics
2 answers:
Sloan [31]3 years ago
5 0

Answer:

It’s C

Step-by-step explanation:

dangina [55]3 years ago
4 0

Commutative property of addition is

a+b = b+a, that is if we change the positions of the numbers, the result is same. For e.g. 2 + 3 = 3+2 .

In the given question , which is (-1+i) + (21+5i), we can use commutative property of addition to simplify it to the simpler form .

And the first step is to combine the like terms that is

(-1+21)+(i+5i). And tht's the required answer or that's the first step which is the commutative property of addition .

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dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

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Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

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P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

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