In this case there will be 2 solutions to solve for in this equation, both will equal plus and minus the answer. Which is 14.
6(3x + 5) = +_ 14
The solutions will be the following :
(14/6 - 5)/3
(-14/6 - 5)/3.
Well first you should divide 10 by 4. Thats 2.5. Then you mulipltiply 2.5 by 15.
Answer: 21 , 72 , 75
Step-by-step explanation:
The one that could represent the three sides of a right angle triangle must obey Pythagoras theorem , that is
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
a = side of right triangle
b = side of right triangle
c = hypotenuse
Let's check the sides one after the other
1. ![21 , 72 , 75](https://tex.z-dn.net/?f=21%20%2C%2072%20%2C%2075)
![21^{2}+72^{2} = 5,625](https://tex.z-dn.net/?f=21%5E%7B2%7D%2B72%5E%7B2%7D%20%3D%205%2C625)
![75^{2}=5625](https://tex.z-dn.net/?f=75%5E%7B2%7D%3D5625)
this means that
![21^{2}+72^{2}=75^{2}](https://tex.z-dn.net/?f=21%5E%7B2%7D%2B72%5E%7B2%7D%3D75%5E%7B2%7D)
this could represent the three sides of a right triangle
2. ![7,8,10](https://tex.z-dn.net/?f=7%2C8%2C10)
![7^{2}+8^{2}=113](https://tex.z-dn.net/?f=7%5E%7B2%7D%2B8%5E%7B2%7D%3D113)
![10^{2}=100](https://tex.z-dn.net/?f=10%5E%7B2%7D%3D100)
![7^{2}+8^{2}\neq 10^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2B8%5E%7B2%7D%5Cneq%20%20%2010%5E%7B2%7D)
3. ![8, 12 , 15](https://tex.z-dn.net/?f=8%2C%2012%20%2C%2015)
![8^{2}+12^{2}= 208](https://tex.z-dn.net/?f=8%5E%7B2%7D%2B12%5E%7B2%7D%3D%20208)
![15^{2}=225](https://tex.z-dn.net/?f=15%5E%7B2%7D%3D225)
![8^{2}+12^{2}\neq 15^{2}](https://tex.z-dn.net/?f=8%5E%7B2%7D%2B12%5E%7B2%7D%5Cneq%20%20%2015%5E%7B2%7D)
4. ![14,84,85](https://tex.z-dn.net/?f=14%2C84%2C85)
![14^{2}+84^{2}=7,252](https://tex.z-dn.net/?f=14%5E%7B2%7D%2B84%5E%7B2%7D%3D7%2C252)
![85^{2} = 7225](https://tex.z-dn.net/?f=85%5E%7B2%7D%20%3D%207225)
![14^{2}+84^{2}\neq 85^{2}](https://tex.z-dn.net/?f=14%5E%7B2%7D%2B84%5E%7B2%7D%5Cneq%20%20%2085%5E%7B2%7D)
Therefore , the only combination that could represent the three sides of a right triangle will be 21 , 72 , 75