The correct answers are "sugar" and "amino acids." We can find this answer within the name itself. The prefix "glyco-" relates to producing sugar (think glucose and glycogen, which are both forms of sugar), and the suffix "proteins" is exactly that: proteins (which are made up of amino acids). So, when we say glycoprotein, we can think "sugar-protein," which gives us our answer.
Answer:
Always include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their own. Explanation:
If two heterozygous individuals are crossed, the results of the cross are as follows:
- SS - spotted condition
- 2 Ss - Spotted condition
- ss - non-spotted condition
<h3>What is an Heterozygous Cross:</h3>
According to this question, the gene coding for spotted condition. The allele for spotted condition (S) is dominant over the non-spotted condition (s).
If two heterozygous Dalmatian dogs are crossed i.e. Ss × Ss, the allele combination for each gamete is as follows:
The following offsprings will be produced:
- SS - spotted condition
- 2 Ss - Spotted condition
- ss - non-spotted condition
Learn more about heterozygous cross at: brainly.com/question/13050360
Answer:
B. As the distance between loci increases, some multiple crossovers go undetected such that the relationship between recombination frequency and map distance ceases to be linear.
Explanation:
When calculating recombination frequencies, and hence, map distances, we might notice that these distances are not completely additive. They might vary. <em>For example, let us say that we have three genes, A, B, and C, in that order. </em>We calculated that the <em>distance between A and B equals 5.9</em> MU and that <em>B and C are 19.5 MU apart.</em> According to this, we might say that the <em>total distance between A and C is 25.4 MU (5.9 + 19.5). </em>However, after a<em> two-point calculation between A and C, the value equals 23.7 MU. </em>
The recombination frequency between these two genes located in the extremes and far apart underestimate the actual genetic distances between them because there might occur other crossing-overs that were not detected. This is <em>when calculating the distance between A and C, we probably will not detect the occurrence of a double recombinant between them, and hence, we might sub-estimate the real distance.</em>
The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci, is not lineal. The farther apart are the two genes, the worse is the distance estimation.
