Answer:
08o8ijhvggyuui8988799999oooo
Answer:
im not sure but
Step-by-step explanation:
Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
Answer:
3.) 0.894
Step-by-step explanation:
✔️First, find BD using Pythagorean Theorem:
BD² = BC² - DC²
BC = 17.89
DC = 16
Plug in the values
BD² = 17.89² - 16²
BD² = 64.0521
BD = √64.0521
BD = 8.0 (nearest tenth)
✔️Next, find AD using the right triangle altitude theorem:
BD = √(AD*DC)
Plug in the values into the equation
8 = √(AD*16)
Square both sides
8² = AD*16
64 = AD*16
Divide both sides by 16
4 = AD
AD = 4
✔️Find AB using Pythagorean Theorem:
AB = √(BD² + AD²)
AB = √(8² + 4²)
AB = √(64 + 16)
AB = √(80)
AB = 8.9 (nearest tenth)
✔️Find sin x using trigonometric ratio formula:
Reference angle = x
Opposite side = BD = 8
Hypotenuse = AB = 8.944
Thus:
(nearest thousandth)