By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
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Answer:
2
Step-by-step explanation:
In 30-60-90
The hypotenuse is always the short leg multiplied by 2
So going backward, 4/2 = 2
#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y
Divide both sides by -4:
Answer:
x= -6-y/4
#7 part 2:
Add <span>y</span><span> to both sides:
</span>-5x=21+y
Divide both sides by -5:
Answer: x=-21+y/5
hope i helped!
Answer:
54° and 110°
Step-by-step explanation:
The opposite angles of a cyclic quadrilateral are supplementary, sum to 180°
(9)
19x - 26 + 7x - 2 = 180
26x - 28 = 180 ( add 28 to both sides )
26x = 208 ( divide both sides by 26 )
x = 8
Then
∠ EFG = 7x - 2 = 7(8) - 2 = 56 - 2 = 54°
(10)
21x - 33 + 14x + 3 = 180
35x - 30 = 180 ( add 30 to both sides )
35x = 210 ( divide both sides by 35 )
x = 6
Then
∠ YVW = 14x + 3 = 14(6) + 3 = 84 + 3 = 87°
The inscribed angle YVW is half the measure of its intercepted arc YW, so
arc YW = 2 × 87° = 174°, then
arc XW = 174° - 64° = 110°
Answer:
60º
Step-by-step explanation:
NXO = MXO - MXN
NXO = 110 - 50
NXO = 60