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rusak2 [61]
4 years ago
8

Sin 3A = cos (A – 70ᵒ), where A is an acute angle then A = ________________ ᵒ.

Mathematics
1 answer:
romanna [79]4 years ago
6 0

Answer:

A = 40°

Step-by-step explanation:

\sin 3A =  \cos (A – 70ᵒ) \\  \\  \cos(90 \degree -  3A) =  \cos (A – 70ᵒ) \\   \{\because \: \cos(90 \degree -   \theta) =  \sin \theta \} \\  \\ (90 \degree -  3A) =   (A – 70ᵒ)  \\  \\ 90 \degree  + 70ᵒ  =   3A  +  A  \\  \\ 160 \degree = 4A \\  \\ A =  \frac{160 \degree}{4}  \\  \\ \huge \red{ \boxed{A =  40 \degree}}

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