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nikklg [1K]
3 years ago
6

Two similar bottles are shown. the smaller bottle can hold 500ml. how much can the larger bottle hold. the smaller bottle is 15

cm in height and the larger bottle is 21 cm in height
what i have written is one mark out of 3

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

1372ml

Step-by-step explanation:

21/15 = 1.4 = Linear Scale Factor

1.4^3=2.744 = Area Scale Factor

500 x 2.744 = 1372ml

tankabanditka [31]3 years ago
5 0

Answer:

If we assume that the bottle is cylindrical and we take the same radius (3.26) of both the bottles (bottles only differ in heights) then the larger bottle will hold approximately 701.14 ml of fluid (the answer says 700ml which is very close)

Step-by-step explanation:

Step 1: Formula of volume of a cylinder is pi*r^2*h

where value of pi is 3.14

r is the radius

h is the height of the bottle (height is different for both bottles)

After putting the values and estimated radius for both as 3.26, we get the volume of the taller bottle.

You can extract the radius by following this method:

Volume of a cylinder = pi*r^2*h (now put the value of the known volume and height of the smaller cylinder)

500 = 3.14 * (r)^2 *15

500/(3.14*15) = r^2

10.616 = r^2

Taking sqrt. on both sides

We get r = 3.26

Now put the same value in the formula of volume with the radius and height. You will get the answer for second bottle.

V= 3.14 * (3.26)^2 *21

V= 701.14 (approx)

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notsponge [240]

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Step-by-step explanation:

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Given the function defined below, what is the value of the 4th term?
MakcuM [25]

Answer:

The 4 t h term is   f(4)   = 143

Step-by-step explanation:

<em>Explanation</em>:-

Given  function f(1) = -4

Given 'nth' term is  f(n) = -3f(n-1) +5

Put n =2         <em> f(2) = -3 f(2-1) +5</em>

                             = -3 f(1) +5

                             = -3 (-4) +5

                             = 12 +5

                       f(2) = 17

put n= 3      

                         f(n) = -3f(n-1) +5  

                      <em>   f(3) = -3 f(3-1) +5</em>

                            = -3f(2) +5

                           = -3(17) +5

                           = -51+5

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Put n=4

                  f(n) = -3f(n-1) +5

               <em>  f(4)  = -3f(4-1) +5</em>

<em>                  f(4)  = -3f(3)+5</em>

                f(4)   = -3(-46)+5

                f(4)   = 138 +5

                f(4)   = 143

<u><em>Final answer</em></u>:-

<em>The 4 t h term is   f(4)   = 143</em>

         

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