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lilavasa [31]
3 years ago
8

Find the equation of a Line , in slope-intercept form of a line that passes throught the point (-5,-1)and is parallel to the lin

e
- 2x +4y =8
(In the picture : The options of answers)​

Mathematics
2 answers:
ipn [44]3 years ago
8 0

Answer: y=x/2 + 3/2

Step-by-step explanation:

tankabanditka [31]3 years ago
3 0

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange - 2x + 4y = 8 into this form by adding 2x to both sides

4y = 2x + 8 ( divide all terms by 4 )

y = \frac{1}{2} x + 2 ← in slope- intercept form

with slope m = \frac{1}{2}

Parallel lines have equal slopes, thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute (- 5, - 1) into the partial equation

- 1 = - \frac{5}{2} + c ⇒ c = - 1 + \frac{5}{2} = \frac{3}{2}

y = \frac{1}{2} x + \frac{3}{2} ← equation of parallel line

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8-1 < √65

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Step-by-step explanation:

Convert 45 yards of ribbon to feet through proper conversion factor.  

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Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 12, b = 14
Eva8 [605]
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°
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