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const2013 [10]
3 years ago
14

18

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Jenny has followed the wrong order of operations, in that she has subtracted before multiplying.

Following the order as directed by PEMDAS

Multiplication is performed before subtraction

Given

12 - 2 × 4 ← perform multiplication

= 12 - 8 ← perform subtraction

= 4

victus00 [196]3 years ago
3 0
She followed the wrong order of operations.
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Lucinda wants to build a square sandbox, but she has no way of measuring angles. Which of the following explains how she can mak
Sati [7]
All of the angles should be the same because a square has all equal angles and side lengths.
6 0
3 years ago
48x32 show the steps please
galina1969 [7]

Answer:

1536

Step-by-step explanation:

steps....?

8 0
3 years ago
With reference to the figure, sin X equals?<br> 1.) 0.250<br> 2.)0.447<br> 3.)0.894<br> 4.)1
Flura [38]

Answer:

3.) 0.894

Step-by-step explanation:

✔️First, find BD using Pythagorean Theorem:

BD² = BC² - DC²

BC = 17.89

DC = 16

Plug in the values

BD² = 17.89² - 16²

BD² = 64.0521

BD = √64.0521

BD = 8.0 (nearest tenth)

✔️Next, find AD using the right triangle altitude theorem:

BD = √(AD*DC)

Plug in the values into the equation

8 = √(AD*16)

Square both sides

8² = AD*16

64 = AD*16

Divide both sides by 16

4 = AD

AD = 4

✔️Find AB using Pythagorean Theorem:

AB = √(BD² + AD²)

AB = √(8² + 4²)

AB = √(64 + 16)

AB = √(80)

AB = 8.9 (nearest tenth)

✔️Find sin x using trigonometric ratio formula:

Reference angle = x

Opposite side = BD = 8

Hypotenuse = AB = 8.944

Thus:

sin(x) = \frac{opp}{hyp} = \frac{8}{8.944} = 0.894 (nearest thousandth)

6 0
3 years ago
Helpgchjsghjcvbxnvbsvjdgasghgbhdvbahgvgbd
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Answer:

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8 0
3 years ago
Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (–4, 0).
8_murik_8 [283]

Answer:

y^{2}=-16x

Step-by-step explanation:

we know that

The standard equation of a horizontal parabola is equal to  

(y-k)^{2}=4p(x-h)

where

(h,k) is the vertex

(h+p,k) is the focus

In this problem we have

(h,k)=(0,0) ----> vertex at origin

(h+p,k)=(-4,0)

so

h+p=-4

p=-4

substitute the values

(y-0)^{2}=4(-4)(x-0)

y^{2}=-16x

8 0
3 years ago
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