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const2013 [10]
3 years ago
14

18

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Jenny has followed the wrong order of operations, in that she has subtracted before multiplying.

Following the order as directed by PEMDAS

Multiplication is performed before subtraction

Given

12 - 2 × 4 ← perform multiplication

= 12 - 8 ← perform subtraction

= 4

victus00 [196]3 years ago
3 0
She followed the wrong order of operations.
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Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Informal letter<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B32%7D%20" id="TexFormula1" title=" \sqrt{32} " alt=" \sqrt{32}
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Answer:

4√2 is the answers for the question

Step-by-step explanation:

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0.5(8x+4) + (2x+ 1)<br><br>k(2x+1)​
julsineya [31]

Try 40x+20+4kxexponet2+4kx+k

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How to solve using substitution
DiKsa [7]
X+5 = x^2 - x + 2
0 = x^2 -2x - 3
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y = -1 + 5 OR y = 3+5
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So we have two ordered pairs, (-1,4) and (3,8).

Hope that helped!

can you mark my answer as brainliest btw?

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What is the product of StartFraction 5 Over 11 EndFraction and Three-fourths?
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Answer:

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Step-by-step explanation:

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