4 years ago

The acid dissociation constant for an acid dissolved in water is equal to the ____.

Chemistry

2 answers:

Darya [45]4 years ago

5 0

<span>equilibrium constant times the concentration of water. - 100% guaranteed correct</span>

erica [24]4 years ago

4 0

Answer:The correct answer is option b.

Explanation:

$HA+H_2O\rightleftharpoons A^-+H_20^+$

The equilibrium constant expression is given as:

$K_{eq}=\frac{[A^-][H_3O^+]}{[HA][H_2O]}$

$K_a=K_{eq}\times [H_2O]=\frac{[A^-][H_3O^+]}{[HA]}$

The acid dissociation constant is product of equilibrium constant and concentration of water.

Hence,from the given options the correct answer is option b.

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