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KengaRu [80]
4 years ago
14

A student records the mass of a piece of iron. The iron is then left outside until it rusts. What type of reaction occurs, and h

ow does the mass of the object after rusting compare with its original mass?
Chemistry
2 answers:
iVinArrow [24]4 years ago
6 0
<span>A student records the mass of a piece of iron. The iron is then left outside until it rusts. The type of reaction that occurs is oxidation reaction. The mass of the object decreases after rusting compared with its original mass.</span>
lapo4ka [179]4 years ago
4 0

Answer:

oxidation reaction

Explanation:

Rusting is the oxidation of iron in the presence of air and moisture. Rusting in a chemical change in which iron combines with oxygen to form iron oxide. The molar mass of iron oxide is greater than iron. So the mass of an object after rusting is greater than its initial mass.

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Which gas law refers to the solubility of a gas changing with the pressure over the solution
Dmitry [639]

Answer:

the answer should be henry's law

6 0
4 years ago
How <br> many moles are in 8.5 •10^25
Bess [88]
You need the chemical to find the answer

7 0
3 years ago
An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the
sukhopar [10]

This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

P_1V_1=P_2V_2

Thus, we solve for the final pressure, P2, to get:

P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm

Learn more about ideal gases: brainly.com/question/8711877

8 0
3 years ago
The successive ionization energies for a given element are listed. How many valence electrons does it have?
damaskus [11]

Answer:

3 valence electrons

Explanation:

Let us first find the amount increased for everything.

From 1st to 2nd,  1048 - 620 = 428

428 increased from 1st to 2nd.

From 2nd to 3d, 2144 - 1048 = 1096

1096 increased from 2nd to 3rd.

From 3rd to 4th, 8724 - 2144 = 6580

6580 increased from 3rd to 4th.

From 4th  to 5th, 10141 - 8724 = 1417

From 3rd to 4th,  it increased the most. Therefore, we assume that those are the beginning core electrons and not valence electrons. Also, starting from 3rd, they are all core electrons.

For the 1st and 2nd,  we can assume they are valence electrons because the kJ/mol didn't increase that much.

Since the core electrons started from the 3rd, we most likely have 3 valence electrons.

So the final answer is 3.

Hope it helped!

5 0
3 years ago
The volcano pictured above is an example of _____________
Natalija [7]
The answer is c, carefully read over and highlight key words
5 0
3 years ago
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