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german
3 years ago
9

Sara has 20 sweets.

Mathematics
1 answer:
nalin [4]3 years ago
3 0

Answer:

The probability that the two sweet will not be same type is \frac{111}{190}

Step-by-step explanation:

P(two sweets not same) = 1 - P( two sweets will be same)

There are 3 possible outcomes where two sweets will be same.

1. it can be two liquor-ice, 2. it can be 2 mint and 3. it can be two humbug

P(two liquor-ice) =\frac{12}{20} \times\frac{11}{19}= \frac{33}{95}

P(two mint) =\frac{5}{20} \times \frac{4}{19} =\frac{1}{19}

P(tow humbug) =\frac{3}{20} \times\frac{2}{19} =\frac{3}{190}

Now we have:

P(two sweets not same) = 1 - P( two sweets will be same)

                                  =1- \left(\frac{33}{95}+ \frac{1}{19}+ \frac{3}{190} \right)

                                   1-\frac{79}{190}

                                   =\frac{111}{190}

Therefore, the probability that the two sweet will not be same type is \frac{111}{190}

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