Question

The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle? 2 cm 2 StartRoot 2 EndRoot cm 4 cm 4 StartRoot 2 EndRoot cm

Answer 1

Answer:

$2\sqrt{2} cm$

Step-by-step explanation:

In order to solve this you just have to remember the formula for the sides and hypotenuse of the triangle rectangle:

$c^{2} =a^{2} +b^{2}$

Since A and B are equal we will use X to represent them both:

$c^{2} =a^{2} +b^{2}\\4^{2} =x^{2} +x^{2}\\16 =2x^{2}\\8=x^{2} \\x=\sqrt{8}=\sqrt{4*2}=2\sqrt{2}$

ANd by solving the equation we get that the length of the legs of the triangle rectangle with a hypotenuse of 4cm is $2\sqrt{2} cm$

Answer 2

Answer:

b.

Step-by-step explanation: