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Zinaida [17]
3 years ago
11

Will mark brainlist Will mark brainlist Will mark brainlist Will mark brainlist Will mark brainlist Will mark brainlist Will mar

k brainlist

Mathematics
2 answers:
I am Lyosha [343]3 years ago
3 0

Answer:

A

Step-by-step explanation:

nalin [4]3 years ago
3 0

A= 125

Step-by-step explanation:

in a triangle all angles add up to 180

Do 180-55= 125

hope this helps :)

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Solve (x+5)+4=16 by first subtracting 4 and then 5. Show your work and justify each step.
Vinil7 [7]
(x+5)+4=16\ \ \ subtract\ 4 \ and \ 5 \ to\ both\ sides \\\\x+5+4-5-4=16-4-5 \\\\x=7


3 0
3 years ago
What is the area of the figure?
Vikentia [17]


1) Striangle = 1/2 * (12-8) * 4 = 1/2 * 4 * 4 = 8 km^2

2) Srectangle = 4 * 8 = 32 km^2

3) Sfigure = 8 + 32 = 40 km^2

Number C

4 0
4 years ago
HELP ASAPA PLS I WILL GIVE BRAIN<br> when did she make her mistake how and how should it be?!!!
Vitek1552 [10]

Answer:

Mistake in step 3

Step-by-step explanation:

3^16/3^-8 should simplify to 3^24 not 3^8

8 0
2 years ago
Read 2 more answers
Help please!<br><br> | 2x^2 + 5x + 3 | &gt; 0<br> solve the inequality
vovikov84 [41]

Factorize the quadratic.

2x^2 + 5x + 3 = (2x + 3) (x + 1)

We have |ab| = |a||b|, so

|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0

Now, both |2x+3|\ge0 and |x+1|\ge0 (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1

So the solution to the inequality is the set

\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}

3 0
2 years ago
I need help with this​
Tju [1.3M]

Answer:

He omitted the value "6" from the input value and added it to the output values. Also, he omitted the value "12" as an output value.

Step-by-step explanation:

Bobby didn't map the relation well. He omitted "6" which is supposed to be an input value and rather included it among the output values (y-values).

"12" was omitted also under output values.

All of these make the the relation not to be a function anymore.

If Bobby had mapped the relation well, the ordered pair would have obviously been a function as every x-value will have exactly one y-value assigned the it.

5 0
3 years ago
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