2 Homeowners'
6 Life
3 Fire
4 Liability
5 Malpractice
1 Automobile
We know that
Part 1)
[surface area of a cone without base]=<span>π*r*l
r=3 in
l=slant height ----> 6 in
</span>[surface area of a cone without base]=π*3*6------> 56.52 in²
[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²
[surface area of the composite figure]=56.52+122.46-----> 178.98 in²
the answer Part A) is
178.98 in²
Part B)
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²
the answer Part B) is
932 ft²
Answer:
NO
Step-by-step explanation:
Let h(t) represent the distance the pack is located above the ground at time t. Then h(t) = 20 ft - 16t^2 ft. Notice how h = 20 ft (the initial height) and that it decreases as t increases.
How long does it take for the pack tohit the ground? Set h(t) = 0 and solve for t:
0 ft = 20 ft - 16t^2 ft yields 16t^2 ft = 20, or t^2 ft = 20/16, which is greater than 1. So the question "Will the backpack hit the ground in 1 second" is answered by NO.
Answer: -2.5f-22
Step-by-step explanation:
you add like terms
The answer is -3
Hope this helps :)
