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3 years ago

Solve the equation pls 4t=32

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

The answer is 6. Because 4x6=32

Sphinxa [80]3 years ago

5 0

To get the answer, you would want t on one side of the equal sign by itself. So, to get rid of the 4, just divide both sides by 4 to get t=8

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I need help finding the domain and range of this graph

SIZIF [17.4K]

Answer:

Step-by-step explanation:

Okay so to find the domain and range we need to find the x values and the y values: the domain is x and the range is y. Therefore the start of our x values can be concluded as -5 and the end is 5, so our domain will be -5 < x < 5: Note, I couldn't put the less than or equal to symbol. SO now our range is the values that are up and down, the range does down at 1 and the range is the highest at 3 so we can determine the range is 1 < y < 3. This is a continuous graph, so there is continuous x values and y values in this graph, so it's simple to use the start and the end of the domain and range followed by the possible y and x values which is represented by y and x.

Hope this helps. :)

8 0

3 years ago

Find the value of x in the triangle shown below

gregori [183]

Answer:

A or 53 squared

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

A video game club charges a fixed annual membership fee of $20 and $2 per video game rented. Let f(n) represent the total annual

Rasek [7]

fixed annual membership fee of $20
$2 per video game rented.
Let f(n) represent the total annual cost of renting n video games
so
f(n) = 20 + 2n

if increased by $15 the next year
then
f(n) = 20 + 2n + 15
f(n) = 2n + 35

answer
f(n) = 2n + 35 (first choice)

5 0

3 years ago

A biologist is researching a newly-discovered species of bacteria. He puts 1,000 bacteria into what he has determined to be a fa

Masteriza [31]

The bacteria grow from 1,000 bacteria into 12,500 bacteria in 12 hours. The exponent function would be
:an= ao(1+r)^t12.500= 1,000(1+r)^121,000(12.5)= 1,000(1+r)^1212.5= (1+r)^121+r= 1.23427r= 0.23Number of bacteria after 20hr would be:an= ao(1+r)^tan= 1,000(1+0.23)^20an= 1,000(62.821 )an= 62,821

8 0

3 years ago