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Rom4ik [11]
3 years ago
8

Which expression is equivalent to a^m + a^n? A, a^m - n B, a^m+n. C, a^m • n d, a^m (divided by) n

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

Option B

Step-by-step explanation:

a^{m} + a^{n} = a^{m+n} ( by using laws of exponents )

Therefore option B is correct

Hope this helps

plz mark as brainliest!!!!!

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If x^2=20 what is the value of x will give brainliest for answer
Schach [20]

Answer:

x² - 20 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{( {b})^{2} - 4ac } }{2a}

a = 1 b = 0 c = -20

So we have

x =  \frac{ - 0 ±  \sqrt{ {0}^{2}  - 4(1)( -20)} }{2(1)}  \\  \\ x =  \frac{± \sqrt{80} }{2}  \\  \\ x =  \frac{±4 \sqrt{5} }{2}  \\  \\  \\ x = ±2 \sqrt{5}  \\  \\  \\ x = 2 \sqrt{5}  \:  \:  \: or \:  \:  \: x =  - 2 \sqrt{5}

Hope this helps you.

8 0
3 years ago
What is the trip fuel cost for a 600 mile trip if the average cost per mile of a car is
larisa [96]

Answer:

C. $114

Step-by-step explanation:

Take the cost per mile times the miles traveled.

0.19 x 600 Multiply

114

4 0
4 years ago
Read 2 more answers
Fundamental Counting Principle (L1)
Kamila [148]
Hope you are having a great day!

STEP BY STEP: a+b(x)=6
4 0
3 years ago
The process of digging a site includes a. carefully recording the location of artifacts. b. accurate descriptions of the artifac
Mice21 [21]

Answer:

The process of digging a site includes

D or B

8 0
4 years ago
Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5
Marianna [84]
\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}

\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)

of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
7 0
3 years ago
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