Good luck to you! I finally figured it out. XD it took a while. I didn’t recall the algebraic approach, if any.
Answer:
The radius of cylinder is 8 inches.
Step-by-step explanation:
We have given,
Volume of cylinder = 320π cubic inches
Height of cylinder = 5 inches
We know, Formula for volume of cylinder as : V =πr²h
where r is radius of cylinder and h is the height of cylinder.
So, We can plug values for V and h to get radius of cylinder.
i.e V = πr²h
320π = πr²* 5
Solving for r.
We get,
320 = r² * 5
320/5 = r²
64 = r²
or r = ±8 , Since radius of cylinder can not a negative number so we neglect -8.
Hence the radius of cylinder is 8 inches.
We have that
<span>the point (7, 1)
case </span><span>A.) y = 5x + 4
if the point </span>(7, 1) lie to the line
so
for x=7 the value of y must be 1
y=5*7+4------> y=39
39 is not 1---------> the point does not belong to the line
case <span>B.) y = -x + 8
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=-7+8------> y=1--------> the point belongs to the line
case <span>C.) y = x - 10
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=7-10------> y=-3
-3 is not 1---------> the point does not belong to the line
case <span>D.) y = -4x + 3
</span>if the point (7, 1) lie to the line
so
for x=7 the value of y must be 1
y=-4*7+3------> y=-25
-25 is not 1---------> the point does not belong to the line
the answer is the option
B.) y = -x + 8
Impossible.
The reason is because there is no way you will get a '7' on a die that is marked 1 - 6. There is no 7.
