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SVEN [57.7K]
3 years ago
6

HELLPPP MEEEEEEE PLEASEEEEE l:(

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer: the answer is 6x-5=36

Step-by-step explanation:

dont blame me this is how i was taught

lesya [120]3 years ago
4 0

Answer:

its the third one

Step-by-step explanation:

You might be interested in
Is DEF a right triangle? True or false
umka2103 [35]
Short answer = false
Remark

If it is a right triangle, it will obey the Pythagorean Equation. a^2 + b^2 = c^2. Let's see if it does.

Equation
a^2 + b^2= c^2
c must be the longest line. (Hypotenuse)

Givens
a = 24
b = 17
c = 40

Sub and Solve
a^2 + b^2 = c^2
17^2 + 24^2 = c^2 [We'll see if this comes out to 40]

289 + 576 = c^2
865 = c^2 which is no where near what 40^2 equals. 40^2 = 1600

Short answer False

Square root of 865 = (865)^1/2 = 29.4
5 0
4 years ago
Which expression below gives the average rate of change of the function g(x)= -x^2 -4x on the interval 6 ≤ x ≤ 8?
DiKsa [7]
The average rate of change of a function, g(x), over an interval [a, b] is given by 

Average\ rate\ of\ change= \frac{g(b)-g(a)}{b-a}

Thus, the average rate of change of g(x)=-x^2-4x over the interval 6\leq x\leq8 is given by:

Average\ rate\ of\ change= \frac{[-(8)^2-4(8)]-[-(6)^2-4(6)]}{8-6} \\  \\ = \frac{(-64-32)-(-36-24)}{2} = \frac{-96-(-60)}{2} = \frac{-96+60}{2} = \frac{-36}{2}  \\  \\ -18
6 0
4 years ago
In the diagram, `stackrel(harr)(PR)` and `stackrel(harr)(AC)` are vertical lines, while `bar(CB)` is a horizontal line segment.
Tomtit [17]

CR:RB = 2:3


CB:CB = 2:5


AQ:AB=2:5


That means we start at A and go 2/5 along the way toward B to get Q:


Q = (-4,-2) + \frac 2 5(1 - -4, -7 - -2) = (-4,-2) + \frac 2 5(5,-5) = (-4,-2)+(2,-2)=(-2,-4)


Answer: Q=(-2,-4)


8 0
3 years ago
Find the HCF of 18 and 24​
Citrus2011 [14]

Answer:

So the greatest common factor 18 and 24 is 6

Step-by-step explanation:

6 0
3 years ago
How can I solve this: |n| ≥ n
valina [46]

|n| \geq n

For n\leq 0

|n| \geq n \Leftrightarrow -n\geq n \Rightarrow 2n\leq0 \Rightarrow n\leq0

For n>0

|n| \geq n \Leftrightarrow n\geq n \Rightarrow 0\geq0\Rightarrow x\in\mathbb{R}

x>0 \vee x\leq 0 \Rightarrow \boxed{x\in\mathbb{R}}

-------------------------------------------------------------

|n| \leq n

For n\leq0

|n|\leq n\Leftrightarrow -n\leq n \Rightarrow 2n\geq 0 \Rightarrow n\geq 0\\
n\geq 0 \wedge n\leq 0 \Rightarrow n=0

For n>0

|n|\leq n \Leftrightarrow n\leq n \Rightarrow 0 \leq 0\Rightarrow n\in \mathbb{R}\\
n\in \mathbb{R} \wedge n>0 \Rightarrow n>0

n>0 \vee n=0 \Rightarrow \boxed{x\geq0}

5 0
4 years ago
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