Answer:
Step-by-step explanation:
First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.
Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.
3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.
add 96+90 to get 186 over 15.
then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.
I hope this helps!
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
b
Step-by-step explanation:
Answer:
104°
Step-by-step explanation:
If segments NO and NM are congruent, then angles NMO and NOM are congruent. So, their supplements, angles NML and NOP are congruent. That is ...
∠NML ≅ ∠NOP = 104°
∠NML = 104°
