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krek1111 [17]
3 years ago
6

Please help! Question above

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

AAS

Step-by-step explanation:

The first A:

∠ABC ≅ ∠DCB

The S:

CB ≅ BC

The second A:

∠A ≅ ∠D

All of them combined to prove ΔABC ≅ ΔDCB through ASA.

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Please answerrrr Graph g(x), where f(x) = 4x − 2 and g(x) = f(x + 1). a line labeled g of x that passes through points 0, negati
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Answer:

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

Step-by-step explanation:

we have

f(x)=4x-2

g(x)=f(x+1)

To determine g(x), substitute the variable x by (x+1) in the function f(x)

so

f(x+1)=4(x+1)-2

f(x+1)=4x+4-2

f(x+1)=4x+2

g(x)=f(x+1)

g(x)=4x+2

therefore

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

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Step-by-step explanation:

according to BODMAS

5×5^2÷5-6

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