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Viefleur [7K]
3 years ago
9

What is the solution to the system -2x + y = 6 and y= 2x - 3?

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0
<span>
replace y= 2x - 3 into </span>-2x + y = 6 

-2x + 2x - 3  = 6 
<span>
- 3 = 6 .....no solutions....


</span>
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Complete the equation of the line through (-9,-9)(−9,−9)left parenthesis, minus, 9, comma, minus, 9, right parenthesis and (-6,0
saw5 [17]

Answer:

The equation of the line is;

y = 3x + 18

Step-by-step explanation:

We want to write the equation of the line through (-9,-9) and (-6,0)

we start by calculating the slope of the line

m = (y2-y1)/(x2-x1) = (0+ 9)/(-6+9) = 9/3 = 3

The general equation of the line is;

y = mx + c

y = 3x + c

To get c, we use any of the points

we substitute for example -6 for x and 0 for y

0 = 3(-6) + c

c = 0 + 18 = 18

So the equation of the line is;

y = 3x + 18

4 0
3 years ago
Question 10 (1 point)
Diano4ka-milaya [45]

Answer:

borh are correct in the same order that you wrote them. fist you eliminate 1 from the orinal side to the other so the next step is also right you subtrac 8 mines 1 so equal to 7 ...

6 0
3 years ago
Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
Round 76 to the nearest tenth
Elden [556K]
The next larger tenth is  76.1 .
The next smaller tenth is  75.9 .

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76 is already rounded to the nearest tenth.
8 0
4 years ago
Read 2 more answers
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
4 years ago
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