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Juliette [100K]
3 years ago
10

How to solve 5x+2y = 39

Mathematics
1 answer:
Julli [10]3 years ago
4 0
X= - 2y/5+ 39/5. hth'

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Identify the parent function that can be used to graph the function f(x) = - 3x +2
Nat2105 [25]

Answer:

f(x)=x

Step-by-step explanation:

We are given with the function f(x) = -3x+2

we have been asked to find the parent function?

As we can see there are two kinds of Tranformation applied here

f(x)+b and f(-ax)

So Here the parent function is f(x)=x

Using the above two mentioned transformations the parent f(x)=x has been converted to f(x) = -3x+2

Hence the parent Function is f(x)=x

6 0
3 years ago
Read 2 more answers
Please help me. please help​
aleksklad [387]

Answer:

<h2><em><u>13</u></em><em><u> </u></em><em><u>years</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em><em><u> </u></em>

No. of children = 5

Ages of the children = 12, 18, 13, 16 and 6 years

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Average age of the children

=  \frac{sum \: of \: the \: ages \: of \: children}{no. \: of \: children}

=  \frac{12 + 18 + 13 + 16 + 6}{5}

=  \frac{65}{5}

= <em><u>13 years (Ans)</u></em>

3 0
3 years ago
A boat cost $16,500 and decreases in value by 13% per year how much will the boat be worth after eight years?
sergeinik [125]

Answer:

$5,415.49

Step-by-step explanation:

Cost of the boat = $16,500

Decrease in value per year = 13%

Worth of the boat in 8 years = ?

Remaining value = 100% - 13%

= 87%

Worth of the boat in 8 years = cost of the boat × remaining value^8

= $16,500 × 87%^8

= $16,500 × 87/100^8

= $16,500 × 0.87^8

= $16,500 × 0.3282116715437121

= $5,415.49

The worth of the boat after 8 years = $5,415.49

5 0
3 years ago
Can someone help me ?
Darina [25.2K]

Answer:

where ever your at looks dark.

Step-by-step explanation:

4 0
3 years ago
Plz help. Attachment below
Vinvika [58]

Answer:

The value of k is 1.

Step-by-step explanation:

You have to apply Indices Law :

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

For this question :

{( \frac{4}{5} )}^{2}  \times  {( \frac{4}{5} )}^{5}  =  {( \frac{4}{5} )}^{6k + 1}

{( \frac{4}{5}) }^{2 + 5}  =  {( \frac{4}{5}) }^{6k + 1}

by \: comparison

2 + 5 = 6k + 1

7 = 6k + 1

7 - 1 = 6k

6k = 6

k = 6 \div 6

k = 1

7 0
4 years ago
Read 2 more answers
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