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3 years ago

What is 8w-8+6w=4w-7

Mathematics

1 answer:

Fiesta28 [93]3 years ago

6 0

8w-8+6w=4w-7
Combine like terms
14w-8=4w-7
Subtract 4w from both sides
10w-8=-7
Add 8 to both sides
10w=1
Divide by 10
w=.1

Hope this helped!

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Xiao’s teacher asked him to rewrite the sum 60+90 as a product of GCF of two numbers and A sum . xiao wrote 3(20+30.what mistake

maks197457 [2]

The first thing we must do for this case is find the factors of each of the numbers.

We have then:

60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

Therefore the GCF is given by:

$GFC = 30$

So, by rewriting the sum we have:

$60 + 90 = 30 (2 + 3)$

The error is not having written the GCF multiplying.

Answer:

Xiao did not write the sum as the product of GCF and the sum of two numbers.

The correct expression is:

$60 + 90 = 30 (2 + 3)$

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3 years ago

Suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at ra

katen-ka-za [31]

Answer:

(a) 350

(b) 175

(d) 196

Step-by-step explanation:

Number of females = 7

Number of males = 5

Total ways of selecting r items from n items is

$^nC_r=\dfrac{n!}{r!(n-r)!}$

(a)

Total ways of selecting 3 females and 2 males.

$\text{Total ways}=^7C_3\times ^5C_2$

$\text{Total ways}=\dfrac{7!}{3!(7-3)!}\times \dfrac{5!}{2!(5-2)!}$

$\text{Total ways}=35\times 10$

$\text{Total ways}=350$

(b)

Total ways of selecting 4 females and 1 male.

$\text{Total ways}=^7C_4\times ^5C_1$

$\text{Total ways}=32\times 5$

$\text{Total ways}=175$

(c)

Total ways of selecting 5 females.

$\text{Total ways}=^7C_5\times ^5C_0$

$\text{Total ways}=21\times 1$

$\text{Total ways}=21$

(d)

Total ways of selecting at least 4 females.

Total ways = 4 females + 5 females

$\text{Total ways}=175+21$

$\text{Total ways}=196$

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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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