The function below takes two parameters: a string parameter: CSV_string and an integer index. This string parameter will hold a
comma-separated collection of integers: '111,22,3333,4'. Complete the function to return the indexth value (counting from zero) from the comma-separated values as an integer. For example, your code should return 3333 (not '3333') if the example string is provided with an index value of 2. Hint: you should consider using the split() method and the int() function.
1 answer:
Answer:
Check the explanation
Explanation:
to complete the function that is to return the indexth value from the comma-separated values as an integer.
and since we've been hinted to consider using the split() method and the int() function.
we'll have to execute the below function which you can also see the screenshot in the attached image.
def get_nth_int_from_CSV(CSV_string,index):
l = CSV_string.split(',')
n = int(l[index])
return n
print(get_nth_int_from_CSV('111,22,3333,4',2))
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Answer:
See explaination
Explanation:
def one_diff(s1,s2):#mthod return true if s1 and s2 has one difference
l1=list(s1)#store characters to list
l2=list(s2)
c=0
if len(l1)!=len(l2):
return False
for i in l1:
if i in l2:#for each character if it is in l1 and l2 continue
continue
else:
c+=1
if c==1:
return True#ret True if cis 1 else False
return False
def exchange(s,*k):#method that exchanges characters
l=list(k)
if len(l)!=0:#check validity of arguments
for i in l:
if i<0 and i+(2*i)>len(s):
res=s
elif i>len(s):
res=s
return res
if len(l)==0:#if no indexes are given
c1=s[0]
c2=s[-1]
res=c2
res=res+s[1:]
res=res[0]+res[1:].replace(c2,c1)
return (res)
elif len(l)==1:#if one index is given
c1=s[l[0]]
c2=s[-1]
res=''
for i in s:
if i==c1 or i==c2:
if i==c2:
res+=c1
else:
res+=c2
else:
res+=i
return (res)
else:#if two indexes are given
c1=s[l[0]]
c2=s[l[1]]
res=''
for i in s:
if i==c1 or i==c2:
if i==c2:
res+=c1
else:
res+=c2
else:
res+=i
return (res)
def is_chain(*k):#method that checks words for one difference
l=list(k)
if len(l)==0:
return False
if len(l)==1:
return True
if len(l)>1:
for i in range(len(l)-1):#for two words in l
if one_diff(l[i],l[i+1]):#call one_diff method
continue
else:
return False
return True
def scramble(s):#method that exchanges characters
i=0
while i<len(s)-1:
s=exchange(s,i,i+1)
i+=2
print(s)
please check out the screenshots in attachment.
