The function below takes two parameters: a string parameter: CSV_string and an integer index. This string parameter will hold a
comma-separated collection of integers: '111,22,3333,4'. Complete the function to return the indexth value (counting from zero) from the comma-separated values as an integer. For example, your code should return 3333 (not '3333') if the example string is provided with an index value of 2. Hint: you should consider using the split() method and the int() function.
1 answer:
Answer:
Check the explanation
Explanation:
to complete the function that is to return the indexth value from the comma-separated values as an integer.
and since we've been hinted to consider using the split() method and the int() function.
we'll have to execute the below function which you can also see the screenshot in the attached image.
def get_nth_int_from_CSV(CSV_string,index):
l = CSV_string.split(',')
n = int(l[index])
return n
print(get_nth_int_from_CSV('111,22,3333,4',2))
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Answer:
(a)Applications Time Stamp Events
(b)S=0.5(W-)+
, where
≤W≤
+8.
Explanation:
Some applications assume that clocks always advance, so they could timestamp events under this assumption.
In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.
We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.
Let us denote the software clock with S.
Then, S=c(W-)+
where:
=The current Time(10:27:54) and;
c is to be found.
We already know that S=+4 when W=
+8,
So:
S=c(W-)+
+4=c(
+8-
)+
4=8c
c=0.5
We obtain the formula
S=0.5(W-)+
, where
≤W≤
+8.