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alexandr1967 [171]
3 years ago
7

Can abnormality exist outside of a cultural context

Physics
1 answer:
aliina [53]3 years ago
3 0
You should search this up and put your own thoughts into it, it’s always good to learn something new!!
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If this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? us
ZanzabumX [31]
"This resolving power" was obviously stated earlier, somewhere before the point where you started copying. With no resolving power specified, there's actually no question, and so no answer.
5 0
3 years ago
The second minimum in the diffraction pattern of a 0.11-mm-wide slit occurs at 0.72°. What is the wavelength of the light?
Anit [1.1K]

Answer:

691.13 nm

Explanation:

d = width of the slit = 0.11 x 10⁻³ m

θ = angle of diffraction pattern = 0.72° degree

λ = wavelength of the light = ?

m = order = 2                              (since second minimum)

for the second minimum diffraction pattern we use the equation

d Sinθ = m λ

Inserting the values

(0.11 x 10⁻³) Sin0.72 = (2) λ

λ = 691.13 x 10⁻⁹ m

λ = 691.13 nm

6 0
3 years ago
A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step
Liula [17]

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

7 0
4 years ago
The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce
Shalnov [3]

Answer:

T_F=\frac{9}{5}(T_K-273)+32

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula T_F=\frac{9}{5}T_C+32 and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula T_C=T_K-273, we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining T_F=\frac{9}{5}(T_K-273)+32.

7 0
3 years ago
What is the density of a sample of sulfur with a volume of 0.6cm
professor190 [17]
The size doesn't matter, the density is always the same. It's 2.07
7 0
4 years ago
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