NEED HELP!!!!! 10 POINTS

Physics

2 answers:

castortr0y [4]3 years ago

6 0

Answer: D.

Explanation:

satela [25.4K]3 years ago

4 0

The answer is D I’m pretty sure

You might be interested in

When light reflects off an object, what is the relation between the angle of incidence and the angle of reflection?

Mashutka [201]

Angle of incidence is the angle when the light strikes an object while angle of reflection is the angle produced when the light strikes off/reflects from the object.

The relation between these two is that both the angles are equal.

The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.

Hope this helps!

7 0

3 years ago

You are on a school bus driving north at 20 m/s. You walk toward the back of the bus with a velocity of 6 m/s. What is your velo

Ganezh [65]

I answered the question but it got deleted?? why?

3 0

3 years ago

Light with a wavelength of 395 nm illuminates a metal cathode. The maximum kinetic energy of the emitted electrons is 0.76 eV .

lutik1710 [3]

Answer:

520.8 nm

Explanation:

We are given that

$\lambda=395 nm=395\times 10^{-9} m$

1 nm= $10^{-9} m$

Maximum kinetic energy, $K_{max}=0.76 eV=0.76\times 1.6\times 10^{-19}$ V

$1 e=1.6\times 10^{-19} C$

We have to find the maximum wavelength of light.

We know that

$h\nu=\frac{hc}{\lambda_0}+K_{max}$

Where $c=3\times 10^8 m/s$

$h=6.625\times 10^{-34}$

$6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}+0.76\times 1.6\times10^{-19}$

$6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}$

$\lambda_0=\frac{6.625\times 10^{-34}\times 3\times 10^8}{6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}}$