Answer:
equation for perpendicular bisector passing through CB is;
y=⁴/³– 5/30
-x - 5 = -11
add 5 to both sides
-x - 5 + 5 = -11 + 5
-x = -6
x = 6
Is there a picture to go with it?
I don’t know if that 2 and 1/4 or 21/4 so I’ll do both.
2 and 1/4 is = 9/4
21/4 is = 5 and 1/4
Hypotenuse² = perpendicular² + base²
H² = 20²+21²
H²= 400+441 = 841
H = √841
H = 29 cm