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kipiarov [429]
3 years ago
5

Which sets of values belongs to the domain and range of a relation

Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0

full answer:

As we know that

The domain of a relation is defined as the set of all possible independent values the relation can really take - basically the group of all possible inputs.

The range of a relation is defined as the set of all possible dependent values the relation can generate from the domain values - basically the group of all possible outputs.

As

The domain is the set of independent values, meaning the set of x-coordinates of the ordered pairs as x is an independent variable.  

The range is set of dependent values, meaning the set of y-coordinates of the ordered pairs as y is an independent variable.

So, in the set of ordered pairs of a relation

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Help me on this please
dusya [7]

Answer:

1. 2 / 5 - Fractional form, 0.4 - Decimal Form

2. 5 / 8 - Fractional form, 0.625 - Decimal Form

3. 6 / 7 - Fractional form, 0.8571 - Decimal Form

4. \sqrt{a / b}

5. \sqrt{a * b}

Step-by-step explanation:

1. \sqrt{4 / 25}

Steps:

1. Divide  - 4 / 25

2. Then take the square root of what you got - \sqrt{0.16} = 0.4

2. \sqrt{25 / 64}

Steps:

1. Divide - 25 / 64

2. Then take the square root of what you got - 5 / 8

3. \sqrt{36 / 49}

Steps:

1. Take the square root of the top number - 6

2. Tage the square root of the bottom number - 7

3. Answer is 6/7.

4. \sqrt{a} / \sqrt{b} = \sqrt{a / b}

5. \sqrt{a}  * \sqrt{b} = \sqrt{a * b}

<em><u>Formula:</u></em>

\sqrt{a} / \sqrt{b} = \sqrt{a / b}

\sqrt{a} * \sqrt{b} = \sqrt{a * b}

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Step-by-step explanation:

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